(2x^2+3x+4)(4x^2-3)=

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Solution for (2x^2+3x+4)(4x^2-3)= equation: 


Simplifying
(2x2 + 3x + 4)(4x2 + -3) = 0

Reorder the terms:
(4 + 3x + 2x2)(4x2 + -3) = 0

Reorder the terms:
(4 + 3x + 2x2)(-3 + 4x2) = 0

Multiply (4 + 3x + 2x2) * (-3 + 4x2)
(4(-3 + 4x2) + 3x * (-3 + 4x2) + 2x2 * (-3 + 4x2)) = 0
((-3 * 4 + 4x2 * 4) + 3x * (-3 + 4x2) + 2x2 * (-3 + 4x2)) = 0
((-12 + 16x2) + 3x * (-3 + 4x2) + 2x2 * (-3 + 4x2)) = 0
(-12 + 16x2 + (-3 * 3x + 4x2 * 3x) + 2x2 * (-3 + 4x2)) = 0
(-12 + 16x2 + (-9x + 12x3) + 2x2 * (-3 + 4x2)) = 0
(-12 + 16x2 + -9x + 12x3 + (-3 * 2x2 + 4x2 * 2x2)) = 0
(-12 + 16x2 + -9x + 12x3 + (-6x2 + 8x4)) = 0

Reorder the terms:
(-12 + -9x + 16x2 + -6x2 + 12x3 + 8x4) = 0

Combine like terms: 16x2 + -6x2 = 10x2
(-12 + -9x + 10x2 + 12x3 + 8x4) = 0

Solving
-12 + -9x + 10x2 + 12x3 + 8x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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